8t^2T+3t-11=0

Solution for 8t^2T+3t-11=0 equation:

8t^2+3t-11=0

a = 8; b = 3; c = -11;
Δ = b2-4ac
Δ = 32-4·8·(-11)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-19}{2*8}=\frac{-22}{16}
=-1+3/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+19}{2*8}=\frac{16}{16}
=1
$